Question

Volume of 1 molecule of water at stp

Answer 1

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Density of water is 1000 g/L.

Density of water is 1000 g/L.The gram molecular mass of water is 18.02.

Density of water is 1000 g/L.The gram molecular mass of water is 18.02.The number of moles in 1 litre = 1000 / 18.02 = 55.5 moles.

Density of water is 1000 g/L.The gram molecular mass of water is 18.02.The number of moles in 1 litre = 1000 / 18.02 = 55.5 moles.1 mole of water = 6.022 x 10^23 molecules of water,So 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water.3.34 x 10^25 molecules of water = 1 litre,1 molecules of water = 1 /3.34 x 10^25= 3.0 x 10^–24 litre.

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Answer 2

Answer:

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Explanation:

Density of water (ρ) = 1g/cm3

Molar mass of water (M) = 18 g/mol

Formula: Molar volume (Vm) = M/ρ

Vm = 18 cm3/mol

Therefore, Volume of 1 molecule of water = Vm/N

Where N is Avogadro number

The volume of 1 molecule of water = 18/(6.022 × 1023)

Volume of 1 molecule of water = 2.989 × 10-23 or 3 × 10-23.