Chemistry, asked by hasan25, 1 year ago

volume of 16M HNO3 taken to prepare 2M HNO3=___mL​

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Answered by Rajdeep11111
5

HELLO THERE!

So we need the volume of 16 Molar Nitric acid to prepare 2 Molar solution of Nitric acid!

We know the formula,

M = \frac{n}{V}

or, n = MV

Where M is the molarity, n is the number of moles, and V is the volume of solution in litres.

We have to prepare 2M, 100 mL solution of nitric acid.

In 2M, 100mL solution, moles of nitric acid:

n = 2 × 0.1 L = 0.2 moles

For 16M solution, 16 moles of HNO₃ are present in 1 litre of solution.

Hence, 0.2 moles will be present in =

\frac{1}{16}\times 0.2\\\\= 0.0125l

So, we need to take 0.0125 litres = 12.5 mL of 16 M Nitric acid to prepare 2M, 100 mL solution of nitric acid.

Thanks!

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