Question

Volume of 16th HNO3 taken for preparing 2M HNO3 (100 ml solution)

Answer 1

HELLO THERE!

Your question seems to be wrong, here's the actual question:

Calculate the volume of 16M Nitric acid taken to prepare 2M Nitric acid (100 mL solution).

Here's your answer:

We know the formula,

$M = \frac{n}{V}$

or, n = MV

Where M is the molarity, n is the number of moles, and V is the volume of solution in litres.

We have to prepare 2M, 100 mL solution of nitric acid.

In 2M, 100mL solution, moles of nitric acid:

n = 2 × 0.1 L = 0.2 moles

For 16M solution, 16 moles of HNO₃ are present in 1 litre of solution.

Hence, 0.2 moles will be present in =

$\frac{1}{16}\times 0.2\\\\= 0.0125l$

So, we need to take 0.0125 litres = 12.5 mL of 16 M Nitric acid to prepare 2M, 100 mL solution of nitric acid.

Thanks!