Question

Volume of 2.8 g of CO at 27 celsius and molar mass of carbon0.0821 is

Answer 1

Formula used :

PV = nRT

​PV = w/M RT

​V = ​w/M RT/P

Given values are :

w = 2.8 g

M = Molar mass of CO = 28 g mol-1

T = 27ºC = (273 + 27) = 300 K

P = 0.821 atm

R = 0.0821 L atm mol-1 K-1

Putting all the values in formula we get :

V = 2.8 g /28 g mol-1 x 0.0821 L atm mol-1 K-1 x 300 K/0.821 atm = 3 L

Hope this helps you .....