Volume of 22gm carbon dioxide at STP
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Answered by
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At STP , 1 mole of Co2 [ 44 grams ] occupies 22.4 litres.
22 g of CO2 ==> x litres.
x = 22/44*22.4 litres. =11.2
Hence, 22 gm carbondioxide occupies 11.2 litres or 11,200 litres at STP
22 g of CO2 ==> x litres.
x = 22/44*22.4 litres. =11.2
Hence, 22 gm carbondioxide occupies 11.2 litres or 11,200 litres at STP
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Answered by
0
Answer:
11.2L
Explanation:
We know, 1 mole of any gaseous substance at STP occupies a volume of 22.4 L. = 11.2 L at STP. Therefore, volume occupied by 22 g of CO₂ at STP is 11.2 L.
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