Question

Volume of a container is 1L it contains a gas at 138atm pressure at 127C temp.. Find the no of moles km the gas

Answer 1

Given:-

• Volume = 1L
• Pressure = 138 atm
• Temoerature = 127 °C

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Need to find:-

• Number of moles in gas = ?

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Solution:-

⋆Volume:

= 1L

= ${10}^{ - 3} {m}^{3}$

⋆ Pressure:

= 138atm

$= 138 \times {10}^{5} pascal$

⋆ Temperature:-

= 127°C

= 127 + 273 K

= 400K

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We know, From IDEAL GAS EQUATION:-

⋆ PV = nRT

We know n = Number of moles ÷ NA

(NA= Avogardo's Number)

$\implies PV= \dfrac{N}{N_A} RT$

$\implies PV = NKT$

$as( \dfrac{R}{N_A}=K)$

$\implies N=\dfrac{PV}{KT}$

Substitute the values:

Number of Molecules = N :

$= \dfrac{138 \times {10}^{5} \times {10}^{ - 3} }{138 \times {10}^{2} \times {10}^{ - 23} \times 400 }$

$= \dfrac{ {10}^{2} \times {10}^{5} \times {10}^{ - 3} \times {10}^{23} }{400}$

$= \dfrac{ {10}^{7} \times {10}^{20} }{400}$

$\red{\boxed{\bold{\large{ = 25 \times {10}^{23}}}}}$

Answer 2

Answer:

Volume = 1L

Pressure = 138 atm

Temoerature = 127 °C

━━━━━━━━━━━━━━━

Need to find:-

Number of moles in gas = ?

━━━━━━━━━━━━━━━

Solution:-

⋆Volume:

= 1L

=  

⋆ Pressure:

= 138atm

⋆ Temperature:-

= 127°C

= 127 + 273 K

= 400K

━━━━━━━━━━━━━━━

We know, From IDEAL GAS EQUATION:-

⋆ PV = nRT

We know n = Number of moles ÷ NA

(NA= Avogardo's Number)

Substitute the values:

Number of Molecules = N :

Explanation: