Question

Volume of a cube is 64000 m3 .Find the cost of painting it total surface at rate of rs5 per m2

Answer 1

Given,

$Volume \: of \: cube = 64000 \: {m}^{3}$

$= > side \: of \: the \: cube = \sqrt[3]{64000} \\ \\ side \: of \: cube \: = 40m$

Now,

$Total surface area of the cube = (6 \times {40}^{2} ) {m}^{2}$

$= > 9600 {m}^{2}$

$the \: cost \: of \: painting it \: total \: surface \: at \: rate \: of r \: s \: 5 per {m}^{2} \: = \frac{9600}{5}$

Cost of panting = Rs 1,920

Answer 2

The cost of painting is 48000 rupees.

Step-by-step explanation:

Consider the provided information.

The volume of the cube is: $V=(a)^3$

Where a is the side of the cube.

Substitute V=64000 in the above formula.

$64000=(a)^3$

$a=\sqrt[3]{64000}$

$a=\sqrt[3]{40\times40\times40}$

$a=40$

The total surface area of cube is: $T.S=6a^2$

Substitute the respective values in the above formula.

$T.S=6(40)^2$

$T.S=6(1600)$

$T.S=9600$

The rate of paint is Rs 5 per m².

Cost of painting = 9600×5=48000

Hence, the cost of painting is 48000 rupees.

#Learn more

Volume of a cube is 5832.Find the cost of painting its total surface area at the rate of 3.50 per m

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