Question

volume of a gas at 0⁰c is 546cm³ if the pressure is kept constant at what temperature will the volume be doubled?​

Answer 1

Explanation:

Explanation:The volume and temperature of a fixed mass of gas under constant pressure are directly proportional. The formula for this gas law is:

Explanation:The volume and temperature of a fixed mass of gas under constant pressure are directly proportional. The formula for this gas law is:V₁/T₁ = V₂/T₂

Explanation:The volume and temperature of a fixed mass of gas under constant pressure are directly proportional. The formula for this gas law is:V₁/T₁ = V₂/T₂Known and Unknown

Explanation:The volume and temperature of a fixed mass of gas under constant pressure are directly proportional. The formula for this gas law is:V₁/T₁ = V₂/T₂Known and UnknownV₁ = initial volume = 546 cm³

Explanation:The volume and temperature of a fixed mass of gas under constant pressure are directly proportional. The formula for this gas law is:V₁/T₁ = V₂/T₂Known and UnknownV₁ = initial volume = 546 cm³T₁ = initial temperature = 0° C + 273.15 = 273 K

Explanation:The volume and temperature of a fixed mass of gas under constant pressure are directly proportional. The formula for this gas law is:V₁/T₁ = V₂/T₂Known and UnknownV₁ = initial volume = 546 cm³T₁ = initial temperature = 0° C + 273.15 = 273 KV₂ = final volume = ? cm³

Explanation:The volume and temperature of a fixed mass of gas under constant pressure are directly proportional. The formula for this gas law is:V₁/T₁ = V₂/T₂Known and UnknownV₁ = initial volume = 546 cm³T₁ = initial temperature = 0° C + 273.15 = 273 KV₂ = final volume = ? cm³T₂ = final temperature = 100° C + 273.15 = 373 K

Explanation:The volume and temperature of a fixed mass of gas under constant pressure are directly proportional. The formula for this gas law is:V₁/T₁ = V₂/T₂Known and UnknownV₁ = initial volume = 546 cm³T₁ = initial temperature = 0° C + 273.15 = 273 KV₂ = final volume = ? cm³T₂ = final temperature = 100° C + 273.15 = 373 KSolve for final volume.

Explanation:The volume and temperature of a fixed mass of gas under constant pressure are directly proportional. The formula for this gas law is:V₁/T₁ = V₂/T₂Known and UnknownV₁ = initial volume = 546 cm³T₁ = initial temperature = 0° C + 273.15 = 273 KV₂ = final volume = ? cm³T₂ = final temperature = 100° C + 273.15 = 373 KSolve for final volume.V₂ = V₁T₂/T₁

Explanation:The volume and temperature of a fixed mass of gas under constant pressure are directly proportional. The formula for this gas law is:V₁/T₁ = V₂/T₂Known and UnknownV₁ = initial volume = 546 cm³T₁ = initial temperature = 0° C + 273.15 = 273 KV₂ = final volume = ? cm³T₂ = final temperature = 100° C + 273.15 = 373 KSolve for final volume.V₂ = V₁T₂/T₁V₂ = (546 cm³ × 373 K)/(273 K) = 746 cm³