Volume of a gas at 0°c is doubled at
Answers
Answered by
2
We apply the relation between V and T
V1/T1 = V2/T2
So let the original volume be V and the final volume will be 2V.
Initial temperature is 0°C which is 273K.
V/273 = 2V/T2
= 546 K
Which is 273°C
I hope this helps you.
Incase you still have doubt feel free to ask.
Similar questions