Question

Volume of a gas at 400 K is 10 L. calculate the decrease in volume of the gas. When it

is cooled to -23 0C pressure remain constant​

Answer 1

Answer:

answer is-6.25

Explanation:

T1=400k

V1=10L

V1=?

T2=-23+273=-250

V1/T1 = V2/T2

=V1×T2/T1

= 10× -250/400

=-6.25