volume of a gas is 25 ml at 273 K and 1 atm what would be the volume if both temperature and pressure are doubled
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Answer:
25ml
Explanation:
v1=25ml=0.025L
v2=?
p1=1atm
p2=2×1=2atm
T1=273k
t2=546k
now by combined gas law
p1v1/t1=p2v2/t2
0.025×1/273=2×v2/546
=0.025l=25ml
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