Volume of CO2 at STP formed when 100ml of 0.1M H2SO4 reacts with excess of Na2CO3 is
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H2SO4+Na2CO3----->Na2SO4+CO2+H2O
No of moles present in 0.1M of 100ml acid=0.1*100/1000=0.01
Now look at the reaction ,
1 mole of acid gives 22.4(standard) lt of carbon dioxide
So 0.01 mole of acid will give =22.4*0.01=0.224lt or 224cm3
So volume of co2 produce =224cm3
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