Volume of co2 obtained at stp by the complete decomposition of nahco3
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Answer:
22.4litres
Explanation:
The balanced reaction for the above will be...
2NaHCO3(s) = Na2CO3(s) + CO2(g) + H2O(g).\
using unitary method or stoichiometry ( whatever you like to call it :) )
2 moles of NaHCO3 gives 1 mole of CO2. Hence the volume will be 22.4 litres.
according to Avogadro's law "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules." hence 1 mole of co2 will have a volume of 22.4 litres.
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