Question

volume of cube is 5832m2.find the cost of painting its tsa at the rate of rs 3.50m2

Answer 1

Formula

We know that :

Volume = side³

Let the side of the cube be a .

Given :

a³ = 5832 m³

= > a = ∛( 5832 m³ )

= > a = ∛( 18 m × 18 m × 18 m )

= > a = 18 m

Find total area

Total surface area of a cube = 6 a²

= > 6 × ( 18 m )²

= > 6 × 324 m²

= > 1944 m²

Find cost

For every 1 m² cost = Rs 3.50

For 1944 m² cost = Rs 1944 × 3.50

                            = Rs 6804

ANSWER :

Rs 6804 would be required for the painting !

Answer 2

Let the side of the cube be a .

now ..

a³ = 5832 m³

=>a = ∛( 5832 m³ )

=> a = ∛( 18 m × 18 m × 18 m )

=> a = 18 m

Find total area
Total surface area of a cube = 6 a²

=> 6 × ( 18 m )²

=> 6 × 324 m²

=> 1944 m²

Find cost
For every 1 m² cost = ₹ 3.50

For 1944 m² cost = ₹ 1944 × 3.50

                            = ₹ 6804

Rs 6804 is required answer

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