Volume of cubiccal box is 39.304cmcube find length of the side of the box solution
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v= 39.304
![{side}^3 = volume \: of \: cube \\ \\ {side}^3 = 39.304 \\ \\ {side} = \sqrt[3]{ 39.304} \\ \\ {side} = \sqrt[3]{ 3.4 \times 3.4 \times 3.4} \\ \\ side = 3.4](https://tex.z-dn.net/?f=+%7Bside%7D%5E3+%3D+volume+%5C%3A+of+%5C%3A+cube+%5C%5C++%5C%5C+%7Bside%7D%5E3+%3D+39.304+%5C%5C++%5C%5C+%7Bside%7D+%3D++%5Csqrt%5B3%5D%7B+39.304%7D++%5C%5C++%5C%5C+++%7Bside%7D+%3D++%5Csqrt%5B3%5D%7B+3.4+%5Ctimes+3.4+%5Ctimes+3.4%7D+%5C%5C++%5C%5C+side+%3D+3.4 "{side}^3 = volume \: of \: cube \\ \\ {side}^3 = 39.304 \\ \\ {side} = \sqrt[3]{ 39.304} \\ \\ {side} = \sqrt[3]{ 3.4 \times 3.4 \times 3.4} \\ \\ side = 3.4")
therefore your answer is 3.4 cm
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therefore your answer is 3.4 cm
mark as brainliest if it is helpful
thank you
;-)
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