Question

volume of cuboid is 7/12 unit's if length =3/4 units and breadth is 1/2 find height of cuboid​

Answer 1

Answer:

Lenght of the box, l = 20 cm

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cm

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10= 2 × 32 × 10

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10= 2 × 32 × 10= 640 cm2

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10= 2 × 32 × 10= 640 cm2Also,

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10= 2 × 32 × 10= 640 cm2Also,Total surface area of the box

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10= 2 × 32 × 10= 640 cm2Also,Total surface area of the box= 2(lb + bh + hl)

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10= 2 × 32 × 10= 640 cm2Also,Total surface area of the box= 2(lb + bh + hl)= 2(20 × 12 + 12 × 10 + 10 × 20)

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10= 2 × 32 × 10= 640 cm2Also,Total surface area of the box= 2(lb + bh + hl)= 2(20 × 12 + 12 × 10 + 10 × 20)= 2(240 + 120 + 200)

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10= 2 × 32 × 10= 640 cm2Also,Total surface area of the box= 2(lb + bh + hl)= 2(20 × 12 + 12 × 10 + 10 × 20)= 2(240 + 120 + 200)= 2 × 560

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10= 2 × 32 × 10= 640 cm2Also,Total surface area of the box= 2(lb + bh + hl)= 2(20 × 12 + 12 × 10 + 10 × 20)= 2(240 + 120 + 200)= 2 × 560= 1120 cm2

Lenght of the box, l = 20 cmBreadth of the box, b = 12 cmHeight of the box, h = 10 cm∴ Surface area of the vertical faces of the box= 2(l + b) × h= 2(20 + 12) × 10= 2 × 32 × 10= 640 cm2Also,Total surface area of the box= 2(lb + bh + hl)= 2(20 × 12 + 12 × 10 + 10 × 20)= 2(240 + 120 + 200)= 2 × 560= 1120 cm2Thus, the surface area of vertical faces and total surface area of the box is 640 cm2 and 1120 cm2, respectively.