Physics, asked by smhp197734, 9 months ago

volume of cylinder is 8 cm cube if the density of cube is 290 gram / Centimetres^3 what is the mass of cylinder.

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Answered by anitgang2004
5

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Answered by Cosmique
10

\large{\underline{\underline{\bf{\red{QuEsTion}}}}}

Volume of cylinder is 8 cm³ . if the density of cylinder is 290 g / cm³ . What is the mass of cylinder.

\large{\underline{\underline{\bf{\red{AnSwEr}}}}}

density = 290 g/cm³

converting it in kg/m³

\bf{density=\frac{290*10^{-3}\:\;kg}{10^{-6}\:\;m^3}=290000\:kg/m^3}

Volume = 8 cm³

Converting it in m³

volume = 8 * 10⁻⁶  m³

As we know,

\boxed{\green{\bf{density=\frac{mass}{volume}}}}

so , on putting values

\mathrm{290000\:\:kg/m^3=\frac{mass}{8*10^{-6}\:m^3}}\\\\{\mathrm{mass=290000*8*10^{-6}\:\; kg}

\boxed{\large{\bf{\blue{mass=2.32\:\;kg}}}}

Therefore,

the mass of cylinder will be 2.32 kg .

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