VOLUME OF DECAMOLAR AQUEOUS SOLUTION OF HYDROCHLORIC ACID IS REQUIRED TO PREPARE 2dm3 of 5M HCl solution is
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As we know
M1v1 = M1v2
1*V = 2*5
V = 10 dm3
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Volume of decamolar aqueous solution of hydrochloric acid required to prepare of 5M HCl solution is
Explanation:
According to the neutralization law,
where,
= molarity of stock solution = 10 M
= volume of stock solution = 3.00 ml
= molarity of diluted solution = 5 M
= volume of diluted solution =
Thus volume of decamolar aqueous solution of hydrochloric acid required to prepare of 5M HCl solution is
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