Question

VOLUME OF DECAMOLAR AQUEOUS SOLUTION OF HYDROCHLORIC ACID IS REQUIRED TO PREPARE 2dm3 of 5M HCl solution is

Answer 1

As we know

M1v1 = M1v2

1*V = 2*5

V = 10 dm3

Answer 2

Volume of decamolar aqueous solution of hydrochloric acid required to prepare $2dm^3$ of 5M HCl solution is $1dm^3$

Explanation:

According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = 10 M

$V_1$ = volume of stock solution = 3.00 ml

$M_2$ = molarity of diluted solution = 5 M

$V_2$ = volume of diluted solution =  $2dm^3$

$10M\times V_1=5M\times 2dm^3$

$V_1=1dm63$

Thus volume of decamolar aqueous solution of hydrochloric acid required to prepare $2dm^3$ of 5M HCl solution is $1dm^3$

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