Question

Volume of dioxygen at STP required for complete combustion of 4 g CH4 is?

Answer 1

CH4 + 2O2 → CO2 + 2H2O

So 1 mole of CH4 requires 2 moles of O2 for complete combustion.

Molar mass of methane = 16 g.

Number of moles of methane in 4 g sample = 4 g/16 g = 1/4 mole.

If 1 mole of CH4 requires 2 moles of O2 for complete combustion.

Therefore,

1/4 mole of CH4 will requires = 1/4 ×2 moles of O2 = 0.5 mol of O2 for complete combustion.

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