volume of frustum and also surface area
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Answer:
volume- 1/3 pie r^2 h
total surface area- pie l (r1+r2) + pie r1^2 +pie r2^2
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Answer:
TSA of a conical frustum = A = π * (r12 + r22 + (r1 + r2) * s) = π * [ r12 + r22 + (r1 + r2) * √((r1 - r2)2 + h2) ]
The volume of a frustum cone=1/3 π h [(R3-r3)/ r]
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