Volume of gas at 27cis 50cm^3. Find the temperature at which it's volume is doubled. If the pressure remain s constant.
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A perfect gas at 27°C is heated at constant pressure till its volume is doubled. What will be its final temperature?
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Using gas equation, we have
(P1*V1) /T1=(P2*V2) /T2 where P=Pressure, V=Volume and T=Absolute temperature of the gas.
Given, P1=P2=P(say) (Since pressure is constant)
V1=V(say), where V is the initial volume of the gas.
Therefore, V2=2V since final volume is double the initial volume.
T1=(27+273)K=300K
T2=?
Substituting the values obtained,in the gas equation, we have
P*V/300=P*2V/T2
Solving, we get T2=final temperature of the gas=600K or (600–273)degree C or 327 degrees C.
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