Volume of gas at St is 1.12*10th to the power - 10L the number of molecules in it is
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mole of gas contains Avogadros number of molecules = $6.022\times 10^{23}.$
So, 1.12×10−71.12×10−7mL is occupied by 6.023×1023×1.12×10−7×224006.023×1023×1.12×10−7×22400 moleules
= 3.0115×10123.0115×1012 molcules.
So, 1.12×10−71.12×10−7mL is occupied by 6.023×1023×1.12×10−7×224006.023×1023×1.12×10−7×22400 moleules
= 3.0115×10123.0115×1012 molcules.
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