Volume of HCl V1 = 20 ml
Strength of HCl N1 = ?
Volume of NaOH V2 (obtained from graph) = …………. ml
Strength of NaOH N2 = 0.2 N
According to the law of volumetric analysis,
V1N1=V2N2
N1 = V2N2 / V1
Strength of HCl = …….. N
Calculation of amount of HCl
The amount of HCl present in 1000 ml of the given solution=Equivalent weight x strength
= 36.46 x ………
= …… g
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