Question

Volume of nitric oxide gas produced by the following reaction of 7 g N2 with excess of oxygen a)22.4dm3 b) 11.2dm3 c) 5.6dm3 d) 2.8 dm3​

Answer 1

Answer:

Given volume of methane =0.25dm

3=0.25L

Combustion of methane (CH 4 )-(methane)CH 4+2O2⟶CO 2+2H 2 O

As we know that volume of 1 mole of gas is 22.4 L.

Amount of oxygen required for the combustion of 22.4 L of methane =(2×22.4)L=44.8L

∴ Amount of oxygen required for the combustion of 0.25 L of methane = 22.444.8 ×0.25=0.5L

Hence, 0.5 L of oxygen required for the complete combustion of 0.25dm 3 of methane.

Answer 2

Answer:

Explanation:11.2dm3