Question

volume of NTP of oxygen required to completely burn 1kg of coal

Answer 1

c + o2 = co2
then,

volume of oxygen = 1000/12 × 22.4
= 1865.9

Answer 2

Answer:

Mass of C = 1000 g

1 moles C requires 1 mole O₂    to burn.

Thus, 83.34 mole C requires 83.34 moles O₂  

At NTP, 1 mole gas occupies 22.4 litres.

83.34 moles occupies 83.34 × 22.4 = 1.86 × 10³  L

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Explanation: