Chemistry, asked by tina2045, 1 year ago

Volume of O2 at stp required for complete combustion of 4g ch4 is

Answers

Answered by dattahari09

25

CH4 +2 O2 =CO2 + 2H2O

from equation

16gm CH4 reacts with 2 x22.4 L of O2

4 GM of CH4 reacts with how much volume of O2?

2 X 22.4 x4 /16 =

11.2 Litres

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