Question

volume of oxygen at NTP evolved at anode due to electrolysis of 18 gm of water is​

Answer 1

Answer:

I don't know sorry I'm in 6th grade

Answer 2

Answer:

11.2 L

Explanation:

$2H_{2}O= 2H_{2}+O_{2}$

Molecular weight of $2H_{2}O$=2×(1×2+16)=2×18=36        

Molecular volume of $O_{2}$=22.4L

So, Volume of  $O_{2}$=22.4×18/36=11.2 L