Question

Volume of oxygen gas obtained at STP on complete
decomposition of 0.2 mol of KCIO3 is
2KClO3 -> 2KCI + 302​

Answer 1

Answer:

The chemical equation for decomposition of KClO

3

can be written as:

2KClO

3

→2KCl+3O

2

245 g of KClO

3

gives 67.2 L of O

2

at STP.

12.25 g of KClO

3

gives

245

67.2

×12.25 =3.36 L.