Question

volume of oxygen required at stp for complete combusution of 1 ​

Answer 1

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Answer 2

C2H4+3O2→2CO2+2H2O

At STP we have

volume of 1 mole of gas = 22400 ml

so, moles of ethene in 20 ml of volume = 224001∗20=0.00089moles

for, 1 mole of ethene we require 3 mole of oxygen

so, for 0.00089 mole of ethene we require oxygen = 0.00089×3=0.00267mole

hence, volume of oxygen require = 22400×0.00267=60ml