Question

volume of oxygen required at stp for complete combusution of 1 mole of ethane
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Answer 1

Answer:

Reaction of the process:

2C2H6 + 7O2= 4CO2+6H2O

We can see in a reaction for the complete combustion of 7 molecules of oxygen is required for 2 moles of ethane.

So for combustion of 1 mole of ethane, oxygen is required =7/2 mole

Answer 2

C2H4+3O2→2CO2+2H2O
At STP we have
volume of 1 mole of gas = 22400 ml
so, moles of ethene in 20 ml of volume = 224001∗20=0.00089moles
for, 1 mole of ethene we require 3 mole of oxygen
so, for 0.00089 mole of ethene we require oxygen = 0.00089×3=0.00267mole
hence, volume of oxygen require = 22400×0.00267=60ml