Question

Volume of solid with 2 hemisphere ends of cylinder of height 4.2and diameter 1.2

Answer 1

Answer:

Total volume of the solid is $5.65 m^3$

Step-by-step explanation:

Volume of the cylinder = $\pi r^2h$

$V= \pi \times 0.6 ^2\times 4.2\\V=1.512 \pi m^3$

Volume the 2 hemisphere is nothing but Volume of the one sphere

$\frac{4}{3} \pi r^3\\=0.288 \pi m^3$

Total volume of the solid = volume of the cylinder + volume of the 2 hemisphere

= $1.512 \pi +0.288 \pi \\=1.8\pi =5.65 m^3$

Total volume of the solid is $5.65 m^3$