Question

volume of two spheres are in the ratio of 67:27. the ratio of their surface area is​

Answer 1

Given

• Volume of two sphere is 64:27

To find

• Ratio of their surface area

Solution

Let the volume of first sphere be v1 and second be V2

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$\sf\red{volume\:of\:sphere=\dfrac{4}{3}\pi\:r^3}$

$\implies\tt\red{\dfrac{V_1}{V_2}=\dfrac{\dfrac{4}{3}\pi\:r_1^3}{\dfrac{4}{3}\pi\:r_2^3}}$

${\implies\tt\red{\dfrac{V_1}{V_2}=\cancel{\dfrac{\frac{4}{3}\pi}\:r_1^3}}\cancel{{\frac{4}{3}}\pi\:r_2^3}}$

=>v1/V2 = 64/27

=>R1/R2 = 4/3

Now surface are of sphere

S1/S2 = 4πR1² / 4πR2²

=>S1/S2 = 16/9

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Hence the surface area of sphere be 16:9

Answer 2

Answer:

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