Volume of water added to convert 0.5 L aqueous
solution of 0.3 M glucose into 0.2 M glucose, is
(1) 0.75 L
(2) 0.5 L
(3) 0.25 L
(4) 0.4 L
Answers
we have to find the volume of water added to convert 0.5 L aqueous solution of 0.3 M glucose into 0.2M glucose.
solution : concept of dilution : during dilution process, no of moles of solute remains constant.
so initial no of moles of solute = final no of moles of solute.
but no of moles of solute = molarity × volume
so, M₁V₁ = M₂V₂
here, M₁ = 0.3M, V₁ = 0.5 L , M₂ = 0.2M , V₂ = ?
⇒0.3 × 0.5 = 0.2V₂
⇒V₂ = 0.75 L
⇒0.5 L + water added = 0.75 L
⇒water added = 0.75 L - 0.5 L = 0.25 L
Therefore volume of water added to aqueous solution of glucose is 0.25 L.
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