Question

volume off a frustum of a cone

Answer 1

Volume of frustum of a cone = π\3 (r1²+r2²+r1xr2)x h

r1 = radius 1
r2 = radius 2
h = height




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Answer 2

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$\Large\fbox{\color{purple}{QUESTION}}$

SURFACE AREA VOLUME FORMULAS

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$\Large\mathcal\green{FRUSTUM}$

$\implies \: tsa = \pi \: l(r1 + r2) + \pi \: {r1}^{2} + \pi {r2}^{2}$

$\implies \: csa = \pi \: l(r1 + r2)$

$\implies volume = \frac{1}{3}\pi \: h( {r1}^{2} + r1.r2 + {r2}^{2} )$

$\implies slant \: hieght = \sqrt{h - ( {r1}^{2} + {r2}^{2}) }$

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