Question

volume require to make 0.1 N HNO3 from 6.3 gram HNO3​

Answer 1

Answer:

First calculate g of compound required =N desired * equivalent mass*volume

(L)

so g required=0.1N*63.01 g/mol*1L=6.301g

V(conc. acid)= g required /(% conc. acid* specific density) =6.301g / (0.65*1.413) =6.86 ml.

Answer 2

Explanation:

Weight of HNO3 = W2 = 6.3 g

Normality of HNO3 = N = 0.1 N

Volume of solution = V = ?

We have,

Equivalent Wt. = 63/1 = 63

Normality = Wt.of Sol. × 1000/Volume × Equivalent Wt.

0.1 = 6.3 × 1000/V*63

=> V = 6.3 × 1000/0.1× 63

=> V = 1000 ml

=> V = 1000 ml

Thus, Volume of HNO3 = 1000 mL Or 1 L