Volume strength of 500ml solution containing 3.4gm
of H,O, is
1) 11.2 2) 6.8 3) 1.12 4.2.24
bition
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Answer:
HI DEAR,
Explanation:
In the above attachment we are calculating molarity for 1M in your question we have first calculate molarity
M=n/V
so we get M= 3.4×1000/34×500=0.2M
HERE n represents no of moles means weight/molecular weight .
molecular weight of H2O2 is 34g .
so for 2M we get
Volume strength =molarity × 11.2 L
0.2×11.2=2.24L
FOR H2O2 TAKE VOLUME AS 11.2 BECAUSE 2 MOLES OF H2O2 GIVES 1 MOLE OF OXYGEN .SO HERE 22.4/2 WE GET 11.2 L
HOPE IT HELPS .
PLEASE MARK AS BRAINLIEST
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