Question

Volumes.
12. To divide a line segment PQ in the ratio 3 : 2, we draw a ray PX such that ZQPX is an acute angle, then we
draw a ray QY || PX such that X and Y are in opposite directions with respect to PQ an​

Answer 1

Given :- To divide a line segment PQ in the ratio 3 : 2, we draw a ray PX such that ∠QPX is an acute angle . Points are marked on PX at equal distances . what is the minimum number of such points ?

Answer :-

Draw a line PQ . from P draw a ray PX such that ∠QPX is an acute angle .

now, mark 5 points on PX at equal distances . The points are marked from P to Q as P1, P2, P3, P4 and P5 . All these lines are drawn parallel to XQ and passing through the marked points on PQ .

So, we can conclude that, these parallel lines will divide PQ in 5 equal parts .

therefore, the minimum number of points are (3 + 2) = 5 (Ans.)

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