Question

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VUDAVL.
There is 384 in a bag in the form of 50p, 25p and 10p coins. If the coins are in the
ratio 7:8:9, respectively, find the number of coins of each type.​

Answer 1

Answer:

Step by step explanation:

There are 384 coins of 50 paise, 25 paise and 10 paise which are in the ratio 7 : 8 : 9 respectively.

Let the common multiple be 'x'.

Thus,

Let total number of coins of 50 paise be 7x ,

Let total number of coins of 25 paise be 8x,

Let total number of coins of 10 paise be 9x.

⟩⟩ 7x + 8x + 9x = 384

» 24x = 384

» x = 16

Thus,

7x = 7 × 16 = 112

8x = 8 × 16 = 128

9x = 9 × 16 = 144

Thus, 50p coins are 112, 25p coins are 128 and 10p coins are 144.

Answer 2

Answer:

Total Money = 384

Denominations = 50 Paise, 25 Paise, 10 Paise

Ratio given = 7:8:9

Let money be in denominations = 7x, 8x, 9x

=> 7x + 8x + 9x = 384

=> 24x = 384

=> x = 16

Number of coins:

50 Paise = 7x = 7 × 16 = 112

25 Paise = 8x = 8 × 16 = 128

10 Paise = 9x = 9 × 16 = 144