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7. Aright triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm.
Find the volume of the solid so obtained.
Answers
GIVEN :
Sides of a right ∆ ABC are 5cm, 12cm and 13cm.
It is revolved about 12cm side. Then it forms as a cone.
Height will be 'h' = 12cm
Radius will be 'r' = 5cm
Here, we have to find the volume of Cone.
We know that,
Volume of cone = 1/3πr²h
= 1/3 × 22/7 × 5² × 12
= 22/7 × 25 × 4
= 22/7 × 100
= 2200/7
= 314.28cm³
Therefore, volume of obtained solid will be 314.28cm².
Answer:
Answer: 314 cm. [ approx. ]
Step by step explanation:
Let Angle B be 90°.
Hence,
Hypotenuse, AC = 13 cm. AB = 12 cm, BC = 5 cm.
Given that,
∆ABC is revolved about the side with 12 cm that is, AB.
Thus, Cone is formed, as a result.
Let radius = r = 5 cm and height= h = 12 cm.
Volume of solid formed = Volume of cone
= 1/3 πr²h
= 1/3 × π × 5 ×5 × 12
= 100π
[We know that, π = 3.14]
= 100 × 3.14
= 314 cm. [ Approx. ]
Hence, The volume of the solid so obtained is 100π cm or 314 cm.