Question

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Let e1e2 are eccentricities of (x)2/16-(y)2/9-1 and (x)2/16+(y)2/(b)2-1 and e1e2 is 1 the foci of the ellipse​

Answer 1

Answer:

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Step-by-step explanation:

Correct option is

C

2e12+e22=3

For ellipse a2=18,b2=4

⇒e1=1−184=37

For hyperbola a2=9,b2=4

⇒e2=1+94=313

Clearly, 2e12+e22=3

Hence, option 'C' is correct.