Question

W=-2,x=3,y=0,z=-1/2 put value in y square-w square/xz

Answer 1

Step-by-step explanation:

General Guidelines for solving these type of questions-

1. Write the value carefully once.

2. Firstly put the values in brackets then chances of mistakes will reduce.

3. Multiply the signs carefully.

4. Then solve the question finally.

Correct Question-

If w = -2, x = 3, y = 2 and z = -1/2 then find the value of

$\sf{ \frac{ {y}^{2} - {w}^{2} }{xz} }$

Solution-:

Given-:

w = -2,

x = 3,

y = 2 and

z = -1/2

So in order to find the value we need to put all the values in the equation as-

$= > \sf{ \frac{ {y}^{2} - {w}^{2} }{xz} } \\ = > \sf{ \frac{ {(0)}^{2} - {(3)}^{ - 2} }{(3 \times - \frac{ 1}{2})}} \\ = > \sf{ \frac{0 - 9}{ - \frac{3}{2} } } \\ = > - 9 \times ( - \frac{2}{3} ) \\ = > \sf{ \frac{ \cancel18}{ \cancel3}} \\ = > 6$

Therefore-:

The value is 6.

Answer 2

Given :---

• w = -2
• x = 3
• y = 0
• z = -1/2

To Find :---- (y² - w²)/xz

Remember :---

• a²-b² = (a+b)(a-b)
• (-a)² = a²
• (-a) × (-b) = ab
• 1/(a/b) = b/a

Putting values now we get,

$\frac{ {y}^{2} - {w}^{2} }{xz} \\ \\ \frac{ {0}^{2} - { (- 2)}^{2} }{3 \times \frac{ - 1}{2} } \\ \\ \frac{0 - 4}{ \frac{ - 3}{2} } \\ \\ - 4 \times \frac{ - 2}{3} \\ \\ = \frac{8}{3}$

So, required answer is $\huge{\frac{8}{3}}$

(Hope it helps you)