Question

Р
w
= 29.
Q.The molar composition of polluted air is as FOLLOWS
percentage composition Gas At. wt.
mole
16%
Oxygen-16
Mavg.
80%
Nitrogen-14
03%
Carbon dioxide
01%
Sulphurdioxide
What is the average molecular weight of the given
polluted air ?
(Given that: atomic weights of C and S are 12 and 32
respectively)​

Answer 1

Answer:

Carbon dioxide

01%

Sulphurdioxide

What is the average molecular weight of the given

polluted air ?

(Given that: atomic weights of C and S are 12 and 32

respectively)dhs siJsvd dksks

Answer 2

Answer:

29.48 grams

Explanation:

If Mole% is given, then

Avg. Molecular mass =

$\frac{m1x1 + m2x2 + m3x3 + m4x4}{100}$

where

m = Molar weight (Gram Molecular weight)

x = Mole%

Now, calculate m1, m2, m3, m4

m1 = 2×16 = 32

m2 = 2×14 = 28

m3 = (1×12)+(2×16) = 44

m4 = (1×32)+(2×16) = 64

x1, x2, x3 and x4 are given as 16, 80, 3 and 1 respectively.

Now Put Values and get Answer.