Math, asked by abrahamlincoln1027, 4 months ago

(w+3)(2w-a)=bw^2 - w+3c​

Answers

Answered by santrakabita86
0

Answer:

(w+3)(2w-a)=bw²-w+3c

2w²-aw+6w-3a=bw²-w+3c

2w²-bw²-aw+w+6w-3a-3c=0

2w²-bw²-aw+7w-3a-3c=0

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