Question

w
9
Find the value of k if kx(x-5)+6=0 havé equal roots.
2.​

Answer 1

Answer:

kx²-5kx+6=0

b²-4ac

25k²-4(k)(6)=0

25k²-24k=0

k(25k-24)=0

k=0

and k=24/25