w and answer the questions that follow
Unlike children, adults can appreciate the valuable projects and relationships in the be
because adults are the sorts of creatures who can endorse many aspects of their lives merely to
conception of what a worthwhile life looks like. A neurotic author who writes brillantes
the project of writing under stress and anxiety because she knows that these negative embons
otherwise be. A brain surgeon operating on the worst types of cancers knows that the stakes in the
carefree manner. She is willing to trade carefreeness for a life of achievement in medicine
In fact, we can evaluate the lives of adults who are not carefree as positive precisely because we
capacities (eg, for self-reflection; to acquire relevant moral knowledge; to maintain an adequate
risks and opportunities attached to certain actions, etc) allow her to endorse valuable projects
towards them are lacking.
The same is not true of children. Although they also need to endorse the valuable projects an
contributions to living well, an endorsement in their case arises when children feel positive e
Children simply lack the requisite evaluative capacities to be able to endorse valuable proje
within an overall life plan.
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Answers
Answer:
(i) (d): Since the coordinates of A and Bare (2, 3) and (2, 1) respectively.
∴ Required distance = AB
=(2−2)2+(1−3)2−−−−−−−−−−−−−−−√=22−−√=2 units
(ii) (b): Since, library is situated at C(4, 1)
∴Required distance = BC
=(4−2)2+(1−1)2−−−−−−−−−−−−−−−√=22+02−−−−−−√=2 units
(iii) (d): Required distance = AC
=(4−2)2+(1−3)2−−−−−−−−−−−−−−−√=22+22−−−−−−√=22√ units
(iv) (b): Since AB = BC ≠ AC, therefore ΔABC is an isosceles triangle.
(v) (d): Distance between O and A
=22+32−−−−−−√=4+9−−−−√=13−−√ units
and distance between O and B =
22+12−−−−−−√=4+1−−−−√=5√ units
Thus, required distance = (13−−√−5√) units
(i) (a): We have, OA = 22√ km
⇒22+y2−−−−−−√=22√
⇒4+y2=8⇒y2=4
⇒y=2(∵y=−2 is not possible )
(ii) (c): We have OB = 82√
⇒x2+82−−−−−−√=82√
⇒x2+64=128⇒x2=64
⇒x=8(∵x=−8 is not possible )
(iii) (c) : Coordinates of A and Bare (2, 2) and (8, 8) respectively, therefore coordinates of point M are
(2+82,2+82)i.e .,(5.5)
(iv) (d): Let A divides OM in the ratio k: 1.Then
2=5k+0k+1⇒2k+2=5k⇒3k=2⇒k=23
∴ Required ratio = 2 : 3
(v) (b): Since M is the mid-point of A and B therefore AM = MB. Hence, he should try his luck moving towards B.
Consider the house is at origin (0, 0), then coordinates of grocery store, electrician's shop, food cart and bus stand are respectively (2, 3), (-4, -6), (6, - 8) and (-6, 8)
(i) (d): Since, grocery store is at (2, 3) and food cart is at (6, -8)
∴ Required distance =(6−2)2+(−8−3)2−−−−−−−−−−−−−−−−√
=42+112−−−−−−−√=16+121−−−−−−−√=137−−−√ cm
(ii) (b): Required distance
=(−6)2+82−−−−−−−−−√=36+64−−−−−−√=100−−−√=10 cm
(iii) (c) : Let 0divides EG in the ratio k : I,then
0=2k−4k+1⇒2k=4⇒k=2
Thus, 0 divides EG in the ratio 2 : 1
Hence, required ratio = OG :OE i.e., 1 : 2
(iv) (c): Since, (0, 0) is the mid-point of (-6,8) and (6, -8), therefore both bus stand and food cart are at equal distances from the house. Hence, required ratio is 1 : 1.
(v) (d): Mid-point of grocery store and electrician's shop is (2−42,3−62), i.e., (−1,−32) Thus, the diagonals does not bisect each other [∵ Mid-point are not same]
Hence, they form a quadrilateral.
(i) (c): Required coordinates are (0,43)
(ii) (c)
(iii) (a): Radius = Distance between (0,0) and (43,0)
=(43)2+02−−−−−−−−√=43 units
(iv) (b): Area of circle = π(radius)2
=π(43)2=169π sq. units
(v) (d): Let the coordinates of the other end be (x,y).
Then (0,0) will bethe mid-point of (1,7√3) and (x, y).
∴(1+x2,7√3+y2)=(0,0)
⇒1+x2=0 and 7√3+y2=0
⇒x=−1 and y=−7√3
Thus, the coordinates of other end be (−1,−7√3)
(i) (c): We have, P( -3,4), Q(3, 4) and R( -2, -1).
∴ Coordinates of centroid of ΔPQR
=(−3+3−23,4+4−13)=(−23,73)
(ii) (d): Coordinates of S= (−3+32,4+42)=(0,4)
(iii) (c): Coordinates of T= (−2+32,−1+42)=(12,32)
(iv) (a): Coordinates of U = (−2−32,−1+42)=(−52,32)
(v) (c): The centroid of triangle formed by joining the mid-points of sides of given triangle is same as that of the given trangle.
So, centroid of ΔSTU=(−23,73)
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case study questions , cbse case study questions for Coordinate G