Question

W can do 25% of a work in 30 days x can do 1/4 of work in 10 days y can do 40% of the work in 40 days z can do 1/3 of the work in 30 days who will complete the work first

Answer 1

w 25% work 30 days
so 100% 120
and x 1/4 work 10 days so complete work 40 days
Y 40% work 40 days 100% work in 100 days
Z 1/3 work in 30 days& complete work 90 days
So,,, X can do it firsf

Answer 2

Given :-

(i) W completes 25% work in 30 days

(ii) X completes 25% work in 10 days

(iii) Y completes 40% work in 40 days

(iv) Z completes 1/3% work in 30 days

Solution :-

For W;

==> 25% of work in 30days

==> 1%of work = 30/25 days

==> 100%of work = (30/25) × 100

==> 100%of work = 120 days

Similarly for X;

==> 1/4 of work (which is 25%) = 10 days

==> 100% of work = (10/25) × 100

==> 100% of work = 40 days

Also we can calculate for Y;

==> Y completes 40% work = 40 days

==> 100% of work = (40/40) x 100

==> 100% of the work = 100 days

And for Z;

==> Z completes 1/3% work = 30 days

==> 100% of the work = (30/33 ) x 100

==> 100% of the work ≈ 90 days

Now we have all the values :-

W = 120days

X = 40 days

Y = 100days

Z = 90 days

We can see from above calculated values that X takes least number of days which is 40 days.

Hence :-

X will finish first.