Question

w= -------- × =---------- × cos O
5×f , 5×d, f×d​

Answer 1

Explanation:

Given :-

Manoj scored twice the runs of Rahul.

Rahul's score 30.

⇝To Find :-

What is the score of Manoj .

⇝Solution :-

{\red{✧}}{\underline{\bf{ Let :}}}✧

Let:

{\large{\purple{\rightarrowtail}}{\bf{Score \: of \: Rahul = 30 \: runs}}}↣ScoreofRahul=30runs

{\large{\purple{\rightarrowtail}}{\bf{Score \: of \: Manoj = x \: runs}}}↣ScoreofManoj=xruns

{\large{\purple{\rightarrowtail}}{\bf{Score \: of \: Manoj = 2x \: runs}}}↣ScoreofManoj=2xruns

{\red{✧}}{\underline{\bf{ Finding \: Age \: of \: manoj :}}}✧

FindingAgeofmanoj:

{\large{:{\longmapsto{\bf{ Runs \: of \: Manoj = 2x(runs \: of \: rahul)}}}}}:⟼RunsofManoj=2x(runsofrahul)

{\large{:{\longmapsto{\bf{ \: \: \: \: \: \: \: \: \: \: \: \: 2x }}}}}:⟼2x

{\large{:{\longmapsto{\bf{ \: \: \: \: \: \: \: \: \: \: \: \: 2 \times 30 }}}}}:⟼2×30

{\large{\purple{:{\longmapsto{\underline{\overline{\boxed{\bf{60 \: Runs}}}}}}}}}:⟼

60Runs

{\red{✧}}{\underline{\bf{ Therefore:}}}✧

Therefore:

{\large{\blue{\twoheadrightarrow{\red{\bf{Runs {\small_{(Manoj)}} = 60 \: Runs}}}}}}↠Runs

(Manoj)

=60Runs

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

Answer 2

Explanation:

Given:

Radius of the circular sheet = 4 cm

Radius of the circle removed = 3 cm

To Find:

Area of the remaining circle.

Solution:

Radius of outer circle = 4 cm

Radius of inner circle = 3 cm

According to the given information,

Area of the outer circle = \pi (4^{2} )= 16\piπ(4

2

)=16π

Area of the inner circle = \pi (3^{2})=9\piπ(3

2

)=9π

Now,

Remaining area = 16\pi -9\pi = 7\pi = 7 \times \frac{22}{7} = 22m^{2}16π−9π=7π=7×

7

22

=22m

2

Therefore :\implies \boxed {Remaining \: area \: of \: the \: sheet \: is \: 22m^{2} }:⟹

Remainingareaofthesheetis22m

2