Question

W. Find the equation of the line passing through (-3,5) and perpendicu
through the points (2, 5) and (-3; 6).​

Answer 1

Answer:

y = 5x + 20

Step-by-step explanation:

A(2 , 5) , B(- 3, 6)

Slope of line passing through the points A and B is

$m_{AB}$ = $\frac{y_{B} - y_{A} }{x_{B} -x_{A} }$ = $\frac{6-5}{-3-2}$ = $-\frac{1}{5}$

y - $y_{A}$ = $m_{AB}$ ( x - $x_{A}$ )

y - 5 = $-\frac{1}{5}$ ( x - 2 ) ⇔ y = $-\frac{1}{5}$ x + $\frac{27}{5}$

Slope of perpendicular line to line AB is

m =  $-\frac{1}{m_{AB} }$ ⇒ m = 5

y - 5 = 5(x + 3) ⇔ y = 5x + 20