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In the equilateral triangle r:R:r1 is
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ANSWER
Let side length be a
⇒r=
S
△
=
4(
2
3a
)
3
a
2
=
2
3
a
3
R=
4△
abc
=
4(
4
3
a
2
)
a
3
=
3
a
r
1
=
S−a
△
=
4×(
2
a
)
3
a
2
=
2
3
a
⇒r:R:r
1
=
2
3
1
:
3
1
:
2
3
×2
3
=1:2:3⇒(C)
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