Math, asked by laxmiravula12, 4 months ago

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Multi Choice Type Question
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In a examination, 1800 candidates were boys
and 2200 were girls. If 42% of boys and 48% of
girls passed the examination, then what is the
overall percentage of candidates who failed?​

Answers

Answered by chaurasiavikas820
1

Step-by-step explanation:

52 percent candicates were failed

Answered by giftyteresa
1

Hii...

Do your sum in this form ......

Number of boys passed the examination=42/100×1800=756

Number of boys passed the examination=42/100×1800=756Number of girls passed the examination=30/100×900=270

Number of boys passed the examination=42/100×1800=756Number of girls passed the examination=30/100×900=270Total number of student passed =756+270=1026

Number of boys passed the examination=42/100×1800=756Number of girls passed the examination=30/100×900=270Total number of student passed =756+270=1026Number of student failed =(1800+900)−1026

Number of boys passed the examination=42/100×1800=756Number of girls passed the examination=30/100×900=270Total number of student passed =756+270=1026Number of student failed =(1800+900)−1026By further calculation

Number of boys passed the examination=42/100×1800=756Number of girls passed the examination=30/100×900=270Total number of student passed =756+270=1026Number of student failed =(1800+900)−1026By further calculation=2700−1026

Number of boys passed the examination=42/100×1800=756Number of girls passed the examination=30/100×900=270Total number of student passed =756+270=1026Number of student failed =(1800+900)−1026By further calculation=2700−1026=1674

Number of boys passed the examination=42/100×1800=756Number of girls passed the examination=30/100×900=270Total number of student passed =756+270=1026Number of student failed =(1800+900)−1026By further calculation=2700−1026=1674Percentage of students failed =1674/2700×100=62%

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